Integrand size = 29, antiderivative size = 73 \[ \int \frac {\cos ^5(c+d x) \sin ^3(c+d x)}{a+a \sin (c+d x)} \, dx=\frac {\sin ^4(c+d x)}{4 a d}-\frac {\sin ^5(c+d x)}{5 a d}-\frac {\sin ^6(c+d x)}{6 a d}+\frac {\sin ^7(c+d x)}{7 a d} \]
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Time = 0.08 (sec) , antiderivative size = 73, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.103, Rules used = {2915, 12, 76} \[ \int \frac {\cos ^5(c+d x) \sin ^3(c+d x)}{a+a \sin (c+d x)} \, dx=\frac {\sin ^7(c+d x)}{7 a d}-\frac {\sin ^6(c+d x)}{6 a d}-\frac {\sin ^5(c+d x)}{5 a d}+\frac {\sin ^4(c+d x)}{4 a d} \]
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Rule 12
Rule 76
Rule 2915
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {(a-x)^2 x^3 (a+x)}{a^3} \, dx,x,a \sin (c+d x)\right )}{a^5 d} \\ & = \frac {\text {Subst}\left (\int (a-x)^2 x^3 (a+x) \, dx,x,a \sin (c+d x)\right )}{a^8 d} \\ & = \frac {\text {Subst}\left (\int \left (a^3 x^3-a^2 x^4-a x^5+x^6\right ) \, dx,x,a \sin (c+d x)\right )}{a^8 d} \\ & = \frac {\sin ^4(c+d x)}{4 a d}-\frac {\sin ^5(c+d x)}{5 a d}-\frac {\sin ^6(c+d x)}{6 a d}+\frac {\sin ^7(c+d x)}{7 a d} \\ \end{align*}
Time = 0.15 (sec) , antiderivative size = 48, normalized size of antiderivative = 0.66 \[ \int \frac {\cos ^5(c+d x) \sin ^3(c+d x)}{a+a \sin (c+d x)} \, dx=\frac {\sin ^4(c+d x) \left (105-84 \sin (c+d x)-70 \sin ^2(c+d x)+60 \sin ^3(c+d x)\right )}{420 a d} \]
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Time = 0.23 (sec) , antiderivative size = 49, normalized size of antiderivative = 0.67
method | result | size |
derivativedivides | \(\frac {\frac {\left (\sin ^{7}\left (d x +c \right )\right )}{7}-\frac {\left (\sin ^{6}\left (d x +c \right )\right )}{6}-\frac {\left (\sin ^{5}\left (d x +c \right )\right )}{5}+\frac {\left (\sin ^{4}\left (d x +c \right )\right )}{4}}{d a}\) | \(49\) |
default | \(\frac {\frac {\left (\sin ^{7}\left (d x +c \right )\right )}{7}-\frac {\left (\sin ^{6}\left (d x +c \right )\right )}{6}-\frac {\left (\sin ^{5}\left (d x +c \right )\right )}{5}+\frac {\left (\sin ^{4}\left (d x +c \right )\right )}{4}}{d a}\) | \(49\) |
parallelrisch | \(\frac {280-315 \cos \left (2 d x +2 c \right )-15 \sin \left (7 d x +7 c \right )+21 \sin \left (5 d x +5 c \right )+35 \cos \left (6 d x +6 c \right )-315 \sin \left (d x +c \right )+105 \sin \left (3 d x +3 c \right )}{6720 d a}\) | \(74\) |
risch | \(-\frac {3 \sin \left (d x +c \right )}{64 a d}-\frac {\sin \left (7 d x +7 c \right )}{448 d a}+\frac {\cos \left (6 d x +6 c \right )}{192 a d}+\frac {\sin \left (5 d x +5 c \right )}{320 d a}+\frac {\sin \left (3 d x +3 c \right )}{64 d a}-\frac {3 \cos \left (2 d x +2 c \right )}{64 a d}\) | \(101\) |
norman | \(\frac {\frac {4 \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d a}+\frac {4 \left (\tan ^{13}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d a}-\frac {12 \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{5 d a}-\frac {12 \left (\tan ^{12}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{5 d a}-\frac {16 \left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{15 d a}-\frac {16 \left (\tan ^{11}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{15 d a}+\frac {464 \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{105 d a}+\frac {464 \left (\tan ^{10}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{105 d a}+\frac {184 \left (\tan ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{105 d a}+\frac {184 \left (\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{105 d a}}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{8} \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}\) | \(221\) |
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Time = 0.25 (sec) , antiderivative size = 67, normalized size of antiderivative = 0.92 \[ \int \frac {\cos ^5(c+d x) \sin ^3(c+d x)}{a+a \sin (c+d x)} \, dx=\frac {70 \, \cos \left (d x + c\right )^{6} - 105 \, \cos \left (d x + c\right )^{4} - 12 \, {\left (5 \, \cos \left (d x + c\right )^{6} - 8 \, \cos \left (d x + c\right )^{4} + \cos \left (d x + c\right )^{2} + 2\right )} \sin \left (d x + c\right )}{420 \, a d} \]
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Leaf count of result is larger than twice the leaf count of optimal. 981 vs. \(2 (53) = 106\).
Time = 32.20 (sec) , antiderivative size = 981, normalized size of antiderivative = 13.44 \[ \int \frac {\cos ^5(c+d x) \sin ^3(c+d x)}{a+a \sin (c+d x)} \, dx=\text {Too large to display} \]
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Time = 0.30 (sec) , antiderivative size = 49, normalized size of antiderivative = 0.67 \[ \int \frac {\cos ^5(c+d x) \sin ^3(c+d x)}{a+a \sin (c+d x)} \, dx=\frac {60 \, \sin \left (d x + c\right )^{7} - 70 \, \sin \left (d x + c\right )^{6} - 84 \, \sin \left (d x + c\right )^{5} + 105 \, \sin \left (d x + c\right )^{4}}{420 \, a d} \]
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Time = 0.33 (sec) , antiderivative size = 49, normalized size of antiderivative = 0.67 \[ \int \frac {\cos ^5(c+d x) \sin ^3(c+d x)}{a+a \sin (c+d x)} \, dx=\frac {60 \, \sin \left (d x + c\right )^{7} - 70 \, \sin \left (d x + c\right )^{6} - 84 \, \sin \left (d x + c\right )^{5} + 105 \, \sin \left (d x + c\right )^{4}}{420 \, a d} \]
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Time = 0.08 (sec) , antiderivative size = 57, normalized size of antiderivative = 0.78 \[ \int \frac {\cos ^5(c+d x) \sin ^3(c+d x)}{a+a \sin (c+d x)} \, dx=\frac {\frac {{\sin \left (c+d\,x\right )}^4}{4\,a}-\frac {{\sin \left (c+d\,x\right )}^5}{5\,a}-\frac {{\sin \left (c+d\,x\right )}^6}{6\,a}+\frac {{\sin \left (c+d\,x\right )}^7}{7\,a}}{d} \]
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